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Nathan Heath,BBC West Investigations

思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。

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The pattern is simple. Instead of loading secrets from a file, you use a wrapper script that fetches secrets from a secure store and injects them as environment variables into your process:

controller.enqueue(processChunk(chunk));